[meteorite-list] mercury escape numbers? can it be this?

From: Walter Branch <waltbranch_at_meteoritecentral.com>
Date: Fri, 5 Aug 2011 13:34:07 -0400
Message-ID: <138EA5A5-D0D6-422D-9EFA-740878DB8364_at_bellsouth.net>

Hi Rex,

Escape velocity depends on the mass of the planet, not it's orbital parameters.

Maybe I don't understand your question. Is this what you are asking?

-Walter

Not everything that can be counted, counts and not everything that counts can be counted. -A. Einstein.

On Aug 5, 2011, at 12:04 PM, rexscates at comcast.net wrote:

> I don't post much.
> I did not do the math. (my calculus has not been used much for many many years.
>
> would not if you had a highly highly elliptical orbit not have to have the full sun escape velocity as it could do the whip around gravitational boost effect from the sun.
>
> also would a highly elliptical orbit have less of a escape velocity?
> the second part could be wrong but the first one is always a possibility. (at least in my mind) :)
>
> -Rex Scates
>
> scalecubes.com
>
>
>
> "But what about Mercury. Mercury's escape velocity is 4.3 km/s. But
>> it's downstream from Earth and the Sun is a huge gravitational drain
>> plug that devours material. If you think Earth gets a piece of Mars,
>> imagine what the Sun gets from Mercury. To escape the Sun ... that is
>> to go upstream towards Earth, at Mercury, any fragment would have to
>> battle an escape velocity of 67.7 km/s. That's greater than Jupiter !
>> You might say ... ok, you don't have to actually escape the Sun, only
>> make it from Mercury to Earth. Well, at Earth, the escape velocity is
>> 42 km/s from the Sun. That's a loss of 25 km/s ... and don't forget
>> the extra 4.3 km/s to get away from Mercury as well ..."
>>
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Received on Fri 05 Aug 2011 01:34:07 PM PDT