[meteorite-list] Fall Times: Theory
From: Sterling K. Webb <kelly_at_meteoritecentral.com>
Date: Thu Apr 22 10:22:34 2004 Message-ID: <3EE1487C.B8AE1F49_at_bhil.com> Hi, All, Watching this thread go by, really glad somebody pointed out that the 32 foot per second figure is really 32 foot per second per second, or an acceleration, not a velocity. Kinda hoped my buddy Gallileo would jump up on the List and explain what that means but I guess he's fiddling with that telescope thingy today, so... OK, you're holding a rock, and the rock is just standing there, then you let go of it. One second later, it's moving at a velocity of 32 feet per second. Since it started out at a velocity of zero and ended up one second later at a velocity of 32 feet per second, it's averaged 16 feet per second for one second: it's fallen 16 feet. --------------------------------------------------------------------------------------- Time Start-of-second Speed End-of-second Speed Fell this second Total --------------------------------------------------------------------------------------- 1 0 32 16 16 2 32 64 48 64 3 64 96 80 144 4 96 128 112 256 And so on. Hey!!! There's a pattern here. The total distance of the fall is: (Number of seconds) ^ 2 x Acceleration ______________________________________ 2 So, if the distance is time*squared times acceleration divided by two, then we can move all those terms around to find that the time for a fall from a given distance is: the square root of (twice the distance divided by acceleration). So, the example given of taking 6 or 7 minutes to fall 63,360 feet is a little off. The fall time for 63,360 feet is 63.93 seconds, or just over a minute. You may remember that one witness to Park Forest estimated the time between the "flash" and the "boom" at "about two minutes." Since sound travels at under 1100 feet per second, that's an altitude of about 125,000 feet, or a fall time of 88.39 seconds. Notice that even though we doubled the altitude, the fall time didn't double. Acceleration is just like compound interest. Remember that the next time you think about jumping out of a transcontinental airliner in the stratosphere (fall time about 45 seconds)! OK, OK, it's a real world and there's real air resistance and at a certain point air resistance may prevent the chunk from gaining any more velocity and if I jump out of an airliner in the stratosphere and flap my overcoat open to the wind, I'll stablize at about 90 mph, but if I dive head first, I'll be going 135 mph when I hit Kansas. First, the source of the fragments may have stagnated (lost most of its velocity) before it breaks up and the gravity fall begins, but this may not always be the case, so there may be an initial velocity to account for. Second, the bigger the fragment the faster it will fall, since mass goes up by the cube and surface area only goes up by the square, so the fragments sort themselves by mass. (That's why the big chunks land at the far end of the strewnfield.) The smaller the fragment, the slower its "terminal velocity" against air resistance. If we throw you down a 1000 foot mine shaft, there'll be this dopplered scream, then strawberry jam at the bottom. If we throw your cat down a 1000 foot mine shaft, there'll be this (higher pitched) dopplered scream, then a cat with a broken ankle at the bottom. If we throw a mouse down a 1000 foot mine shaft, there'll be no scream at all, then a dazed but perfectly healthy mouse at the bottom, saying, "What the hell was that all about?!" Sterling K. Webb (Disclaimer: I am not responsible for those who attempt to duplicate this experimental procedure with either persons or cats. Mice at your own [and mouse's] risk.) Received on Fri 06 Jun 2003 10:05:49 PM PDT |
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