[meteorite-list] Sand Dunes and Meteorites
From: Matson, Robert <ROBERT.D.MATSON_at_meteoritecentral.com>
Date: Thu Apr 22 09:50:21 2004 Message-ID: <AF564D2B9D91D411B9FE00508BF1C8698E5B35_at_US-Torrance.mail.saic.com> This message is in MIME format. Since your mail reader does not understand this format, some or all of this message may not be legible. ------_=_NextPart_001_01C1D9D1.8CF56810 Content-Type: text/plain; charset="iso-8859-1" On the subject of remote sensing of meteorites from above, Jim Hartman wrote: > I know that I am not the rocket scientist here & this may be an oversimplified > theory but I have a picture of my house & my fathers house taken from a > satellite in orbit. Now I may be wrong but I kinda think that if someone is > going to go to the trouble of putting millions of dollars of equipment into > orbit that they would include thermal imaging as part of that inventory. Rocket scientist chiming in: many thermal imaging sensors are currently in orbit (e.g. Landsat, EOS, Spot). But the trouble with all of them is insufficient resolution. Even if you could get 2-meter resolution data in a waveband of interest, a meteorite with a 10-cm x 10-cm "footprint" would only fill one 400th of a pixel. In order to detect such a meteorite with a signal-to-clutter ratio of 3:1, the difference between your target radiance and background radiance would need to be 800 times the standard deviation of the scene gradient. It's not completely impossible, but you're going to need a very benign background and a significant emissivity difference between the background and the meteorite. Temperature difference ends up buying you very little in this case because the target represents such a small fraction of the area of a pixel. For instance, to double the radiance output of a 300 K object in the 3-5 micron band, you'd need to increase its temperature to 320 K -- 36 deg F warmer. What this all boils down to is that you need a sensor flying at low altitude in order to get the footprint size down to something more comparable to the size of the meteorites you expect to find... --Rob ------_=_NextPart_001_01C1D9D1.8CF56810 Content-Type: text/html; charset="iso-8859-1" <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> <HTML><HEAD> <META HTTP-EQUIV="Content-Type" CONTENT="text/html; charset=iso-8859-1"> <TITLE>Message</TITLE> <META content="MSHTML 5.00.3315.2870" name=GENERATOR> <STYLE></STYLE> </HEAD> <BODY bgColor=#ffffff> <DIV><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>On the subject of remote sensing of meteorites from above, Jim Hartman wrote:</SPAN></FONT></DIV> <DIV> </DIV> <DIV><FONT face="Courier New"><FONT size=2><SPAN class=090581421-01042002>> </SPAN>I know that I am not the rocket scientist here & this may be an oversimplified<SPAN class=090581421-01042002><FONT color=#0000ff> </FONT></SPAN></FONT></FONT></DIV> <DIV><FONT face="Courier New"><FONT size=2><SPAN class=090581421-01042002><FONT color=#0000ff>></FONT></SPAN> theory but I have a picture of my house & my fathers house taken from a<SPAN class=090581421-01042002><FONT color=#0000ff> </FONT></SPAN></FONT></FONT></DIV> <DIV><FONT face="Courier New"><FONT size=2><SPAN class=090581421-01042002><FONT color=#0000ff>></FONT></SPAN> satellite in orbit. Now I may be wrong but I kinda think that if someone is<SPAN class=090581421-01042002><FONT color=#0000ff> </FONT></SPAN></FONT></FONT></DIV> <DIV><FONT face="Courier New"><FONT size=2><SPAN class=090581421-01042002><FONT color=#0000ff>></FONT></SPAN> going to go to the trouble of putting millions of dollars of equipment into<SPAN class=090581421-01042002><FONT color=#0000ff> </FONT></SPAN></FONT></FONT></DIV> <DIV><FONT face="Courier New"><FONT size=2><SPAN class=090581421-01042002><FONT color=#0000ff>></FONT></SPAN> orbit that they would include thermal imaging as part of that inventory.<SPAN class=090581421-01042002><FONT color=#0000ff> </FONT></SPAN></FONT></FONT></DIV> <DIV><SPAN class=090581421-01042002></SPAN> </DIV> <DIV><SPAN class=090581421-01042002><FONT color=#0000ff face="Courier New" size=2>Rocket scientist chiming in: many thermal imaging sensors are currently in</FONT></SPAN></DIV> <DIV><SPAN class=090581421-01042002><FONT color=#0000ff face="Courier New" size=2>orbit (e.g. Landsat, EOS, Spot). But the trouble with all of them is</FONT></SPAN></DIV> <DIV><SPAN class=090581421-01042002><FONT color=#0000ff face="Courier New" size=2>insufficient </FONT></SPAN><SPAN class=090581421-01042002><FONT color=#0000ff face="Courier New" size=2>resolution. </FONT></SPAN><FONT face="Courier New"><FONT size=2><FONT color=#0000ff><SPAN class=090581421-01042002>Even if you could get 2-meter resolution data in</SPAN></FONT></FONT></FONT></DIV> <DIV><FONT face="Courier New"><FONT size=2><FONT color=#0000ff><SPAN class=090581421-01042002>a waveband of interest, a meteorite </SPAN></FONT></FONT></FONT><FONT face="Courier New"><FONT size=2><FONT color=#0000ff><SPAN class=090581421-01042002>with a 10-cm</SPAN><SPAN class=090581421-01042002> x</SPAN></FONT></FONT></FONT><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002> 10-cm "footprint" would</SPAN></FONT></DIV> <DIV><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>only fill one 400th of a pixel. </SPAN></FONT><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>In order to detect </SPAN></FONT><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>such a meteorite with</SPAN></FONT></DIV> <DIV><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>a signal-to-clutter ratio of </SPAN></FONT><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>3:1, the difference between </SPAN></FONT><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>your target</SPAN></FONT></DIV> <DIV><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>radiance and background radiance </SPAN></FONT><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>would need to be 800 times </SPAN></FONT><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>the standard</SPAN></FONT></DIV> <DIV><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>deviation of the scene gradient. </SPAN></FONT><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>It's not completely impossible, but</SPAN></FONT></DIV> <DIV><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>you're going to need a very benign </SPAN></FONT><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>background and a significant</SPAN></FONT></DIV> <DIV><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>emissivity difference between the background </SPAN></FONT><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>and the meteorite.</SPAN></FONT></DIV> <DIV><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002></SPAN></FONT> </DIV> <DIV><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>Temperature difference ends up buying you very little in this case because</SPAN></FONT></DIV> <DIV><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>the targe</SPAN></FONT><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>t </SPAN></FONT><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>represents such a small fraction of the area of a pixel. For</SPAN></FONT></DIV> <DIV><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>instance, </SPAN></FONT><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>to double the </SPAN></FONT><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>radiance output of a 300 K object in the 3-5 micron</SPAN></FONT></DIV> <DIV><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>band, you'd need to </SPAN></FONT><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>increase </SPAN></FONT><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>its temperature </SPAN></FONT><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>to 320 K -- 36 deg F warmer.</SPAN></FONT></DIV> <DIV><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002></SPAN></FONT> </DIV> <DIV><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>What this all boils down to is that y</SPAN></FONT><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>ou need a sensor flying at low</SPAN></FONT></DIV> <DIV><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>altitude </SPAN></FONT><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>in order to get the footprint size down to something more</SPAN></FONT></DIV> <DIV><FONT color=#0000ff face="Courier New" size=2><SPAN class=090581421-01042002>comparable to the size of the meteorites you expect to find... --Rob</SPAN></FONT></DIV></BODY></HTML> ------_=_NextPart_001_01C1D9D1.8CF56810-- Received on Mon 01 Apr 2002 06:04:17 PM PST |
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